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Difference between revisions of "Proth's theorem"

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(typos fixed)
(Changing notation to modern form and correcting converse)
 
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Proth's theorem (1878) states:
 
Proth's theorem (1878) states:
  
Let <math>n = h*2^k+1</math> and <math>h<2^k</math>; then <math>n</math> is prime if (and only if) there is an integer <math>a</math> such that
+
Let <math>p = k*2^n+1</math> and <math>k < 2^n</math>; then <math>p</math> is prime if there is an integer <math>a</math> such that
:<math>a^{(n-1)/2} \equiv -1 (mod\,n)</math>.
+
:<math>a^{(p-1)/2} \equiv -1\pmod{p}</math>.
  
A prime of this form is known as a [[Proth prime]].
+
Furthermore, if <math>a</math> is a [[quadratic residue|quadratic non-residue]] modulo <math>p</math>, then the converse is also true.
 +
 
 +
A prime <math>p</math> of this form is known as a [[Proth prime]].
  
 
==External links==
 
==External links==
 
*[[Wikipedia:Proth's theorem|Wikipedia]]
 
*[[Wikipedia:Proth's theorem|Wikipedia]]
 +
 
[[Category:Primality tests]]
 
[[Category:Primality tests]]

Latest revision as of 18:15, 28 September 2023

This article is about Proth's theorem.

Proth's theorem (1878) states:

Let [math]\displaystyle{ p = k*2^n+1 }[/math] and [math]\displaystyle{ k \lt 2^n }[/math]; then [math]\displaystyle{ p }[/math] is prime if there is an integer [math]\displaystyle{ a }[/math] such that

[math]\displaystyle{ a^{(p-1)/2} \equiv -1\pmod{p} }[/math].

Furthermore, if [math]\displaystyle{ a }[/math] is a quadratic non-residue modulo [math]\displaystyle{ p }[/math], then the converse is also true.

A prime [math]\displaystyle{ p }[/math] of this form is known as a Proth prime.

External links